Tentukan jarak titik B dan rusuk TD.
Jawab: BD = √(AB² + AD²)
BD = √(3² + 3²)
BD = √(9 + 9)
BD = √18
BD = √(9 x 2)
BD = 3√2 cm
BO = 1/2 BD
BO = 1/2 x 3√2
BO = (3/2)√2 cm
TO = √(TB² - OB²)
TO = √(6² - (3/2)√2²)
TO = √(36 - 9/4(2))
TO = √(144 - 18)/4
TO = √(126/4)
TO = √(9 x 14)/4
TO = (3/2)√14 cm
Cari jarak titik B ke rusuk TD (BP) dengan memanfaatkan kesamaan luas segitiga TBD
1/2 . a . t = 1/2 . a . t
1/2 . TO . BD = 1/2 . BP . TD
1/2 . (3/2)√14 . 3√2 = 1/2 . BP . 6
(9/2)√28 = 6 . BP
9√28 = 12 . BP
BP = (9/12)√28
BP = 3/4 . √(4 x 7)
BP = 3/4 . 2 √7
BP = (3/2)√7 cm
2. Diketahui limas segi enam beraturan T.ABCDEF dengan panjang rusuk AB = 10 cm dan AT = 13 cm.
Tentukan jarak antara titik B dan rusuk TE.