2. Jarak bayangan ke cermin
Jawab:
1 / f = 1 / s + 1 / s’
1 / - 6 = 1 / 3 + 1 / s’
1 / -6 – 1 / 3 = 1 / s’
-1 – 2 /6 = 1 / s’
S’ = 2 cm
Perbesaran bayangan
M = (s' / s)
M = (2 / 3)
2. Jarak bayangan ke cermin
Jawab:
1 / f = 1 / s + 1 / s’
1 / - 6 = 1 / 3 + 1 / s’
1 / -6 – 1 / 3 = 1 / s’
-1 – 2 /6 = 1 / s’
S’ = 2 cm
Perbesaran bayangan
M = (s' / s)
M = (2 / 3)
Editor: Annisa Fadilla