AC = √132 – 52
AC = √169 – 25
AC = √144
AC = 12 cm
d) ∆DCB ≅ ∆DFE, maka BC = EF
AF + DF + CD = AC
AF + AF + AF = AC
3AF = AC
3AF = 12 cm
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Minggu, 19 Mei 2024 -
Network
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Network
AC = √132 – 52
AC = √169 – 25
AC = √144
AC = 12 cm
d) ∆DCB ≅ ∆DFE, maka BC = EF
AF + DF + CD = AC
AF + AF + AF = AC
3AF = AC
3AF = 12 cm
Editor: Annisa Fadilla
Sumber: buku.kemdikbud.go.id
