a = 1
b = - 5
c = 6
(x1 – 3) + (x2 – 3) = x1 – 3 + x2 – 3
= x1 + x2 – 6
= (- b/a) – 6
= (- (-5/1) – 6
= 5 – 6 = -1
(x1 – 3) + (x2 – 3) = x1. x2 - 3 x1 - 3 x2 + 9
= (c/a) – 3 (x1 + x2) + 9
a = 1
b = - 5
c = 6
(x1 – 3) + (x2 – 3) = x1 – 3 + x2 – 3
= x1 + x2 – 6
= (- b/a) – 6
= (- (-5/1) – 6
= 5 – 6 = -1
(x1 – 3) + (x2 – 3) = x1. x2 - 3 x1 - 3 x2 + 9
= (c/a) – 3 (x1 + x2) + 9
Editor: Suci Annisa Caroline
Sumber: Buku Kemendikbud