Kunci Jawaban Matematika Kelas 8 halaman 291 Ayo Kita Berlatih 10.2 Bab 10, Peluang Teoretik Semester 2

a. komplemen mata dadu kembar?
Pembahasan:

n(S) = 6 x 6 = 36
Titik sampel kejadian A = {(1,1), (2,2), (3,3), (4,4), (5,5), (6,6)}
n(A) = 6

n(A') = n(S) - n(A) = 36 - 6 = 30
P(A') = n(A')/n(S) = 30/36 = 5/6

Baca Juga: Kunci Jawaban Seni Budaya Kelas 7 Halaman 188, Manfaat Terlibat Langsung dalam Pertunjukan Tari

b. jumlah mata dadu 7?
Pembahasan:

n(S) = 36
Titik sampel kejadian A = {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}
n(A) = 6

P(A) = n(A)/n(S) = 6/36 = 1/6

c. jumlah mata dadu 8?
Pembahasan:

n(S) = 36
Titik sampel kejadian A = {(2,6), (3,5), (4,4), (5,3), (2,6)}
n(A) = 5

P(A) = n(A)/n(S) = 5/36