= ½ x 112
= 56 satuan luas
3 (AE + FC) = AEF
L∆DEF = …
3 (AE + FC) = 4 EF
¾ = EF/AE + FC
EF : AE + FC = 3 : 4
Nilai perbandingannya =
EF = 3
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Minggu, 19 Mei 2024 -
Network
-
Network
= ½ x 112
= 56 satuan luas
3 (AE + FC) = AEF
L∆DEF = …
3 (AE + FC) = 4 EF
¾ = EF/AE + FC
EF : AE + FC = 3 : 4
Nilai perbandingannya =
EF = 3
Editor: Muhammad Khusaini
Sumber: buku.kemdikbud.go.id
