(e) Luas permukaan kerucut
s = √8² + 15²
s = √64 + 225
s = √289 = 17 dm
Lp = πr(r + s)
Lp = 3,14 × 8 dm × (8 dm + 17 dm)
Lp = 25,12 dm × (25 dm)
Lp = 628 dm²
(f) Luas permukaan kerucut
t = √2² - 1²
-
Jumat, 24 Mei 2024 -
Network
-
Network
(e) Luas permukaan kerucut
s = √8² + 15²
s = √64 + 225
s = √289 = 17 dm
Lp = πr(r + s)
Lp = 3,14 × 8 dm × (8 dm + 17 dm)
Lp = 25,12 dm × (25 dm)
Lp = 628 dm²
(f) Luas permukaan kerucut
t = √2² - 1²
Editor: Moch. Kharisson Abdillah
Sumber: Buku Kemdikbud
