r1.2 = -b ±√b2 -4ac/2a
r1.2 = -3√2 ±√(3√2)2 – 4 . 1 . (-6)/2 . 1
r1.2 = -3√2 ±√18 + 24/2
r1.2 = -3√2 ±√42/2
r2 = -3√2 ±√42/2
b) Diketahui:
V1 = 12π m3
V2 = 324π m3
d1 = 8 m
r1 = 4 m
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Senin, 20 Mei 2024 -
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r1.2 = -b ±√b2 -4ac/2a
r1.2 = -3√2 ±√(3√2)2 – 4 . 1 . (-6)/2 . 1
r1.2 = -3√2 ±√18 + 24/2
r1.2 = -3√2 ±√42/2
r2 = -3√2 ±√42/2
b) Diketahui:
V1 = 12π m3
V2 = 324π m3
d1 = 8 m
r1 = 4 m
Editor: Annisa Fadilla
Sumber: buku.kemdikbud.go.id
