Lp = 4π (4 + 4√10)
Lp = 16 (1 + √10) π cm2
(2) Volume Kerucut
V = 1/3 π r2t
V = 1/3 π. 42. 12
V = π . 16 . 4
V = 64 π cm3
b) Diketahui: d = 12 cm, maka r = 6 cm
s = 10 cm
Lp = 4π (4 + 4√10)
Lp = 16 (1 + √10) π cm2
(2) Volume Kerucut
V = 1/3 π r2t
V = 1/3 π. 42. 12
V = π . 16 . 4
V = 64 π cm3
b) Diketahui: d = 12 cm, maka r = 6 cm
s = 10 cm
Editor: Muhammad Khusaini
Sumber: buku.kemdikbud.go.id