Network
Ukuran ==> frekuensi ==> fk
40 - 46 ==> 5 ==> 5
47 - 53 ==> 7 ==> 12
54 - 60 ==> 14 ==> 26
61 - 67 ==> 10 ==> 36
68 - 74 ==> 4 ==> 40
___ +
40
Kita cari kelas mediannya :
1/2n = 1/2.40 = 20
Urutan ke 20 berada di 26
sehingga kelas mediannya = 54 - 60
Tb = 54 - 0,5 = 53,5
∑fs = 5 + 7 = 12
fme = 14
C = 7
= 60 - 54 = 6 + 1 = 7
Me = Tb + 1/2 n - ∑fs
_________ .C
fme
Me = 53,5 + 1/2.40 - 12
__________ . 7
14
