1/5 (2
log 3 x 7)
1/5 (2 2
log 3 + log 7)
1/5 (b + a)
f). 2
log 3V24
pembahasan :
24 = 8 x3
2
log 24 1/3
1/3 (2
log 2^3 x 3)
1/3 (3 2 2
log 2 + log 3)
1/3 (3 + b)
5. log 2 = m
log 3 = b