x2 – 1 = 0
x2 = 1
x = ± √1
x = 1 atau x = -1
Cara 3: Rumus abc
x2 – 1 = 0
a = 1
b = 0
c = 1
x1,2 = -b ± √b2 - 4ac/2a
x2 – 1 = 0
x2 = 1
x = ± √1
x = 1 atau x = -1
Cara 3: Rumus abc
x2 – 1 = 0
a = 1
b = 0
c = 1
x1,2 = -b ± √b2 - 4ac/2a
Editor: Suci Annisa Caroline
Sumber: buku.kemdikbud.go.id